69th treasure [text]

[captainash]

Oh glorious network bursting with arcane and forbidden knowledge, please answer my query if you can.

How many pokéballs would it take to fill a 36-cubic-metre ball pit?

Comments

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[captainash]

Not that much of one, really. My team wants to do something fun, so I was looking at options. And since it's a ball pit, wouldn't using pokéballs to fill it be fitting?

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[schachmeister]

Yes, I suppose that would be fitting, but wouldn't it be more expensive than using regular balls?

Though, if you want the look of having a ball pit filled with pokeballs, I'm sure they sell regular balls that look like pokeballs. And that way there would be no danger of any pokemon accidentally getting caught.

Unless, of course, that was your actual master plan. In which case, I apologise for foiling it early.

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[captainash]

Terribly expensive indeed! Even more than I'd estimated, actually. And terribly uncomfortable besides, but that part's not actually unexpected. Of course, painted balls would offer the same visuals, but it feels like a shortcut, you know?

Honestly, I hadn't planned for any 'accidental' captures. Not that I'd reject any wild Pokémon that wants to participate, the more the merrier and all that. Though it'd be something of a false advertisement, if a wild Pokémon allowed itself to be caught thinking ball pits are a regular team activity.

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[schachmeister]

If that is your concern, what keeps you from turning it into a regular team activity? You will already have the balls, right? It would be a bit of a waste to only use them once.

Also, as for your original question -- it's been a while since I had to do math like this, but I believe the amount would depend on the exact dimensions of your ball pit. And whether it is square or circular.

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[captainash]

Renting the pit itself does involve its own cost. So do the permit and the space to set it up, for that matter. I live in an apartment, after all, so I had to find an appropriate location.

The company I'm leaning towards offers square pits, as it happens. Which makes calculating the maximum number of perfectly-placed spheres relatively simple, but is that truly representative of the number of spheres necessary for a pit that's actively used?